2x^2-4x^2+x-2=0

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Solution for 2x^2-4x^2+x-2=0 equation: 



2x^2-4x^2+x-2=0

We add all the numbers together, and all the variables

-2x^2+x-2=0

a = -2; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-2)·(-2)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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